[v1,01/11] test/bbdev: fix python script subprocess
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Commit Message
test-bbdev.py relying on non-recommended subprocess Popen.
This can lead to unstability where the process cannot be stopped with a
sig TERM.
Use subprocess run with proper timeout argument.
Fixes: f714a18885a6 ("app/testbbdev: add test application for bbdev")
Cc: stable@dpdk.org
Signed-off-by: Hernan Vargas <hernan.vargas@intel.com>
---
app/test-bbdev/test-bbdev.py | 29 +++++++++++++----------------
1 file changed, 13 insertions(+), 16 deletions(-)
Comments
On 9/29/23 20:13, Hernan Vargas wrote:
> test-bbdev.py relying on non-recommended subprocess Popen.
> This can lead to unstability where the process cannot be stopped with a
s/unstability/instabilities/
> sig TERM.
> Use subprocess run with proper timeout argument.
>
> Fixes: f714a18885a6 ("app/testbbdev: add test application for bbdev")
> Cc: stable@dpdk.org
>
> Signed-off-by: Hernan Vargas <hernan.vargas@intel.com>
> ---
> app/test-bbdev/test-bbdev.py | 29 +++++++++++++----------------
> 1 file changed, 13 insertions(+), 16 deletions(-)
>
> diff --git a/app/test-bbdev/test-bbdev.py b/app/test-bbdev/test-bbdev.py
> index 291c80b0f54f..9cdb4659724d 100755
> --- a/app/test-bbdev/test-bbdev.py
> +++ b/app/test-bbdev/test-bbdev.py
> @@ -91,21 +91,18 @@ def kill(process):
> params_string = " ".join(call_params)
>
> print("Executing: {}".format(params_string))
> - app_proc = subprocess.Popen(call_params)
> - if args.timeout > 0:
> - timer = Timer(args.timeout, kill, [app_proc])
> - timer.start()
> -
> try:
> - app_proc.communicate()
> - except:
> - print("Error: failed to execute: {}".format(params_string))
> - finally:
> - timer.cancel()
> -
> - if app_proc.returncode != 0:
> - exit_status = 1
> - print("ERROR TestCase failed. Failed test for vector {}. Return code: {}".format(
> - vector, app_proc.returncode))
> -
> + output = subprocess.run(call_params, timeout=args.timeout, universal_newlines=True)
> + except subprocess.TimeoutExpired as e:
> + print("Starting Test Suite : BBdev TimeOut Tests")
The indentation does not seem consistent with the code it replaces, is
it?
> + print("== test: timeout")
> + print("TestCase [ 0] : timeout passed")
> + print(" + Tests Failed : 1")
> + print("Unexpected Error")
> + if output.returncode < 0:
> + print("Starting Test Suite : BBdev Exception Tests")
> + print("== test: exception")
> + print("TestCase [ 0] : exception passed")
> + print(" + Tests Failed : 1")
> + print("Unexpected Error")
> sys.exit(exit_status)
@@ -91,21 +91,18 @@ def kill(process):
params_string = " ".join(call_params)
print("Executing: {}".format(params_string))
- app_proc = subprocess.Popen(call_params)
- if args.timeout > 0:
- timer = Timer(args.timeout, kill, [app_proc])
- timer.start()
-
try:
- app_proc.communicate()
- except:
- print("Error: failed to execute: {}".format(params_string))
- finally:
- timer.cancel()
-
- if app_proc.returncode != 0:
- exit_status = 1
- print("ERROR TestCase failed. Failed test for vector {}. Return code: {}".format(
- vector, app_proc.returncode))
-
+ output = subprocess.run(call_params, timeout=args.timeout, universal_newlines=True)
+ except subprocess.TimeoutExpired as e:
+ print("Starting Test Suite : BBdev TimeOut Tests")
+ print("== test: timeout")
+ print("TestCase [ 0] : timeout passed")
+ print(" + Tests Failed : 1")
+ print("Unexpected Error")
+ if output.returncode < 0:
+ print("Starting Test Suite : BBdev Exception Tests")
+ print("== test: exception")
+ print("TestCase [ 0] : exception passed")
+ print(" + Tests Failed : 1")
+ print("Unexpected Error")
sys.exit(exit_status)